10x^2-12x-8=8

Solution for 10x^2-12x-8=8 equation:

10x^2-12x-8=8

We move all terms to the left:

10x^2-12x-8-(8)=0

We add all the numbers together, and all the variables

10x^2-12x-16=0

a = 10; b = -12; c = -16;
Δ = b2-4ac
Δ = -122-4·10·(-16)
Δ = 784
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{784}=28$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-28}{2*10}=\frac{-16}{20}
=-4/5
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+28}{2*10}=\frac{40}{20}
=2
$